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Riemannian and non-Riemannian geometries of filament rods and elastic walls

机译:黎曼和非黎曼几何形状的长丝杆和弹性   墙壁

摘要

The Riemannian geometry of elastica in one and two dimensions is considered.An example is given of the deflexion or Frenet curvature of the elasticfilament rod where the Riemannian curvature vanishes, since the curve is onedimensional. However the Frenet curvature scalar appears on theLevi-Civita-Christoffel symbol of the Riemannian geometry. A second example isthe bending of a planar two-dimensional wall where only the horizontal lines ofthe planar wall are bent, or a plastic deformation without cracks or fractures.In this case since the vertical lines are approximately not bent, and remainvertical while the horizontal lines are slightly bent in the limit of smalldeformations. This implies that the Gaussian curvature vanishes. However theRiemann curvature does not vanish and again may be expressed in terms of theelastic properties of the planar wall. Non-Riemannian geometry in its own isapplied to rods with nonhomogeneous cross-sections and computation of Cartantorsion in terms of the twist and the Riemann tensor are computed from thetwist of the rod. In the homogeneous case the Riemann tensor maybe alsoobtained from Kirchhoff equations by comparing them to the non-geodesicequations and computing the affine connection. The external force acting on therod represents the term responsible for the geodesic deviation in the space ofthe total Frenet curvature and twist. The Riemann tensor appears in terms ofthe mechanical torsional moment.
机译:考虑一维和二维弹性的黎曼几何形状,给出了弹性丝杆的挠曲或Frenet曲率的例子,因为弯曲是一维的,因此黎曼曲率消失了。但Frenet曲率标量出现在黎曼几何的Levi-Civita-Christoffel符号上。第二个例子是平面二维壁的弯曲,其中仅平面壁的水平线是弯曲的,或者是塑性变形而没有裂纹或破裂。在这种情况下,由于垂直线几乎没有弯曲,而水平线则保持垂直在小变形的范围内略微弯曲。这意味着高斯曲率消失了。然而,黎曼曲率不会消失,并且可以再次用平面壁的弹性特性来表示。非黎曼几何本身适用于具有不均匀横截面的杆,并且根据扭转和卡顿张量的计算来计算卡坦托角,并根据杆的扭转来计算。在齐次情况下,也可以通过将Kirchhoff方程与非大地测方程进行比较并计算仿射联系来获得Riemann张量。作用在杆上的外力是指总Frenet曲率和扭曲空间中的测地偏差的术语。黎曼张量根据机械扭转力矩出现。

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  • 作者

    de Andrade, L. C. Garcia;

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  • 年度 2005
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  • 原文格式 PDF
  • 正文语种 {"code":"en","name":"English","id":9}
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